(2r^2+6r+7)-(3r^2+5r+8)=0

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Solution for (2r^2+6r+7)-(3r^2+5r+8)=0 equation: 



(2r^2+6r+7)-(3r^2+5r+8)=0

We get rid of parentheses

2r^2-3r^2+6r-5r+7-8=0

We add all the numbers together, and all the variables

-1r^2+r-1=0

a = -1; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·(-1)·(-1)
Δ = -3
Delta is less than zero, so there is no solution for the equation

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